Question 179755
[(y^2 -6y + 9) /8] * [(4y + 12) / (y^2 -9)]

Factor where you can:

[(y-3)^2/8] * [4(y+3)/(y-3)(y+3)]

Cancel any factor that is common to a numerator and a denominator,
such as (y-3), 4, (y+3) :

[1/2] * [1/1]

= 1/2
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Cheers,
Stan H.