Question 179736
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Let <i>s</i> be the measure of a side of the square.


Then *[tex \Large 2s - 8] is the measure of a side of the triangle.


The perimeter of an equilateral triangle is 3 times the length of a side.  The perimeter of a square is 4 times the length of a side.  Hence:


*[tex \Large 3(2s - 8) = 4s]


Just solve the equation for <i>s</i>




John
*[tex \LARGE e^{i\pi} + 1 = 0]
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