Question 179689
{{{i^32=1}}} {{{i^1=i}}}
:
{{{i^(-33)}}}={{{1/i^33=1/i^32i^1=1/(1)(i)=highlight(1/i)}}}
:
1/i
:
multiply top and bottom by -i
:
{{{-i/(-i^2)=(-i)/1=highlight(-i)}}}