Question 179681
please help me solve this equation: {{{x^3-5x^2-2x+24;k=-2    f(k)=0}}}
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It's not an equation, as it has no equal sign. But the info about the k implies it is = 0.
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You state one zero, the -2, so (x+2) is a factor.
{{{x^3-5x^2-2x+24}}}
={{{(x+2)*(x^2 - 7x + 12)}}}
= (x+2)(x-3)(x-4)
x = -2
x = 3
x = 4