Question 179620
I will do one. and get you started on the other.. you must multiply by the conjugate to get rid of the complex number in the denominator
:
1.3+i√5/3-i√5
:so we have {{{(1.3+i*sqrt(5))/(3-i*sqrt(5))}}}
:
so the conjugate of  {{{3- sqrt (5)}}} is {{{3 +i*sqrt (5)}}}
:

{{{(1.3+i*sqrt (5))(3 +i*sqrt (5))/(3-i*sqrt( 5))(3 +i*sqrt (5))}}}
:
{{{(3.9+2.3i*sqrt(5)-5)/(9+5)}}}
:

{{{(1.1-2.3i*sqrt(5))/14}}}
:
:
:
 2.4-i√2/i√2 the conjugate for this is {{{-i*sqrt(2)}}} repeat what took place in the problem I just solved...multiplying both top and bottom by the conjugate