Question 179558
LET X, X+1 & X+2 BE THE THREE CONSECUTIVE INTEGERS.
2X+4(X+1)=2(X+2)+20
2X+4X+4=2X+4+20
6X-2X=24-4
4X=20
X=20/4
X=5 FOR THE SMALLER INTEGER.
5+1=6 FOR THE MIDDLE INTEGER.
5+2=7 FOR THE LARGEST INTEGER.
PROOF:
2*5+4*6=2*7+20
10+24=14+20
34=34