Question 179548
{{{9^x + 5 = 50}}}
Subtract {{{5}}} from both sides
{{{9^x = 45}}}
Note that I can write {{{9^x}}} this way:
{{{9*9^(x - 1)}}}
That's the same as saying {{{2^4 = 2*2^3}}}
{{{9*9^(x - 1) = 9*5}}}
Divide both sides by {{{9}}}
{{{9^(x - 1) = 5}}}
This is the same as
{{{log(9,5) = x - 1}}}
{{{x = log(9,5) + 1}}}
I can use the formula which says:
{{{log(b,x) = (log(k,x)) / (log(k,b))}}} with {{{k = 10}}}
{{{log(9,5) = log(5)/log(9)}}}
{{{log(9,5) = .69897 / .95424}}}
{{{log(9,5) = .73249}}}
{{{x = log(9,5) + 1}}}
{{{x = .73249 + 1}}}
{{{x = 1.73249}}} answer
check:
{{{9^x + 5 = 50}}}
{{{9^1.73249 + 5 = 50}}}
{{{45.00032 + 5 = 50}}}
{{{50.00032 = 50}}} close enough