Question 179489
{{{y + 1 = 2(x - 2) }}} Start with the second equation.



{{{highlight(2x - 5) + 1 = 2(x - 2) }}} Plug in {{{highlight(y) = 2x - 5}}}. In other words, replace each "y" with {{{2x-5}}}



{{{2x-5+1=2x-4}}} Distribute.



{{{2x-4=2x-4}}} Combine like terms on the left side.



{{{2x=2x-4+4}}} Add {{{4}}} to both sides.



{{{2x-2x=-4+4}}} Subtract {{{2x}}} from both sides.



{{{0x=-4+4}}} Combine like terms on the left side.



{{{0x=0}}} Combine like terms on the right side.



{{{0=0}}} Simplify.



Since this equation is <font size=4><b>ALWAYS</b></font> true for any x value, this means x can equal any number. 



So there are an infinite number of solutions.



This means that the system is consistent and dependent