Question 179429
A= 2prh + 2pr^2
{{{A = 2*pi*rh + 2*pi*r^2}}}
{{{2*pi*rh = A - 2*pi*r^2}}}
{{{h = (A - 2*pi*r^2)/(2*pi*r)}}}
Nothing cancels.
You can make it:
{{{h = A/(2pi*r) - r}}}