Question 179366
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*[tex \Large \text {         } \math (n-5)^2 = 20]


Take the square root of both sides remembering to consider both positive and negative roots:


*[tex \Large \text {         } \math n - 5 = \small \pm \LARGE sqrt{20}]


Add 5 to both sides:


*[tex \Large \text {         } \math n = 5 \small \pm \LARGE sqrt{20}]


The factors of 20 are *[tex \Large 2 \times 2 \times 5] so you can say:


*[tex \Large \text {         } \math n = 5 \pm sqrt{4} sqrt{5} = 5 \pm 2 sqrt{5}]



John
*[tex \LARGE e^{i\pi} + 1 = 0]
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