Question 179357
the length of a rectangle is 5 feet more than it's width. the area of the rectangle is 176 sq ft. find the length and the width of the rectangle
:
A=L*W......eq 1
L=W+5......eq 2
A=176......eq 3
:
take L's value of W+5 from eq 2 and A's value of 176 and plug them into eq 1
:
176=(W+5)W
:
{{{176=W^2+5W}}}
:
{{{W^2+5W-176=0}}}
:
W=11 and -16...throw out the negative value
:
{{{highlight(W=11)}}}width
:
{{{highlight(L=11+5)}}}length

*[invoke solve_quadratic_equation 1, 5, -176]