Question 179296
Solve the equation :(8/(x+1))-(5/2)=(4/(3x+3)) 
x= 
I need help solving this problem for x. I know I multiply the denominators by 6(x+1) but after that I am not sure what to do. Any help with this problem will be greatly appreciated. Thank you


YOU MULTIPLY THE NUMERATORS BY 6(x+1)BECAUSE 6(x+1) IS THE LOWEST COMMON DENOMINATOR.  THIS WILL GET RID OF THE FRACTIONS:

8/(x+1))-(5/2)=(4/(3x+3)) and this equals 8/(x+1))-(5/2)=(4/3(x+1)) 
{{{(8/(x+1))*6(x+1)-(5/2)*6(x+1)=(4/3(x+1))*6(x+1)}}}=
{{{48-15(x+1)=8}}}=
{{{48-15x-15=8}}} =
{{{33-15x=8}}}subtract 33 from each side
{{{-15x=-25}}}
{{{x=25/15=5/3}}} or one and two thirds----------------ans

CK
{{{8/((5/3)+1)-5/2=4/(3*(5/3)+3)}}}=
{{{8/(8/3)-5/2=4/8}}}=
{{{3-5/2=1/2}}}=
{{{6/2-5/2=1/2}}}
{{{1/2=1/2}}}

Hope this helps----ptaylor