Question 179180
y=ax^2+bx+c the form of a quadratic equation.
y=-x^2+10
a=-1, b=0 c=10
a is negative so the parabla has a maximum (opens downward).
The domain (of x) is all real numbers.
.
The maximum is (-b^2-4ac)/4a
(-0^2-(4*-1*10))/4
=40/4=10
.
The range (for y) is 10 to, but not including, -infinity or [10, -infinity)
.
Ed
.
{{{graph(500,500,-10,10,-12,12,10-x^2)}}}