Question 179137
John and Tony start from Grays lake at the same time and head for a town 10 miles away. John walks twice as fast as Tony and arrives 3 hours before Tony. Find how fast each walks? 
:
I don't why you need a chart for this:
:
Let s = Tony's speed
then
2s = John's speed
:
Write a time equation: Time = {{{dist/speed}}}
:
Tony's time - John's time = 3
{{{10/s}}} - {{{10/(2s)}}} = 3
Multiply eq by 2s
2(10) - 10 = 3(2s)
20 - 10 = 6s
s = {{{10/6}}}
s = 1{{{2/3}}} mph is Tony's speed
and
2 * 1{{{2/3}}} = 3{{{1/3}}} mph is John's speed
:
:
Check solution using decimals
10/1.67 = 6,00
10/3.33 = 3.00
----------------
differ  = 3.00