Question 179118
let x and y be the price of admission and cost per ticket respectively
:
x+6y=34.......eq 1
x+8y=42.......eq 2
:
subtract eq 2 from eq 1
:
x terms are eliminated because x-x=0. We are left with 6y-8y=34-42
:
-2y=-8
:
{{{highlight(y=4)}}}price per ticket
:
take y's value and plug it into either eq 1 or 2. I chose eq 1
:
x+6(4)=34
:
x+24=34
:
{{{highlight(x=10)}}}price of admission