Question 179101
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*[tex \Large \frac{1}{4} y - 8 = \frac{1}{10} y]


The only question is do you really mean *[tex \Large \frac{1}{4} y - 8 = \frac{1}{10} y] or do you mean *[tex \Large \frac{1}{4} (y - 8) = \frac{1}{10} y]?


First way:


Multiply by 40:


*[tex \Large 10y - 8 = 4y]


Add 8 to both sides and -4y to both sides:


*[tex \Large 6y = 8]


Multiply both sides by *[tex \frac {1}{6}]:


*[tex \Large y = \frac {8}{6} = \frac {4}{3}]

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Second way:


Multiply by 40:


*[tex \Large 10y - 80 = 4y]


Add 80 to both sides and -4y to both sides:


*[tex \Large 6y = 80]


Multiply both sides by *[tex \frac {1}{6}]:


*[tex \Large y = \frac {80}{6} = \frac {40}{3}]


John
*[tex \LARGE e^{i\pi} + 1 = 0]
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