Question 179108
Biting an unpopped kernel of popcorn hurts! As an experiment, a self-confessed connoisseur of cheap popcorn carefully counted 773 kernels and put them in a popper. After popping, the unpopped kernels were counted. There were 86. 
(a) Construct a 90 percent confidence interval for the proportion of all kernels that would not pop. 
p-hat = 86/773 = 0.1113
E = 1.645*[0.1113*0.8887/sqrt(773)] = 0.0058
90% CI: 0.1113-0.0058 < p < 0.1113 + 0.0058
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(b) Check the normality assumption.
Check np > 5 and nq > 5
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(c) Try the Very Quick Rule. Does it work well here? Why, or why not?
I'm not familiar with that Rule
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(d) Why might this sample not be typical?
One person's sample is not necessarily representative of the population.
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Cheers,
Stan H.