Question 179066
*[Tex \LARGE \frac{(3.7)^x (3.7)^{-1}}{(3.7)^{-4}}=(3.7)^{2}] Start with the given equation.




*[Tex \LARGE (3.7)^x (3.7)^{-1-(-4)}=(3.7)^{2}] Subtract the exponents.



*[Tex \LARGE (3.7)^x (3.7)^{3}=(3.7)^{2}] Combine like terms.



*[Tex \LARGE (3.7)^x=\frac{(3.7)^{2}}{(3.7)^{3}}] Divide both sides by {{{(3.7)^3}}}.


*[Tex \LARGE (3.7)^x=(3.7)^{2-3}] Subtract the exponents.



*[Tex \LARGE (3.7)^x=(3.7)^{-1}] Combine like terms.




Since the bases are equal, this means that the exponents are equal. So the answer is {{{x=-1}}}