Question 178990
ok we need to complete the square with the y terms
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{{{9x^2+9y^2-6y-17=0.}}}given
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{{{9(y^2-(2/3)y+1/9)+9x^2-17-9=0}}}setting up for completing square.factored out a 9 from the terms {{{9y^2-6y}}} added and subtracted 1/9 so as to complete the square and keep the equation equivilent.
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{{{9(y-(1/3))^2+9x^2-17-1/9=0}}}completed the square
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{{{9(y-(1/3))^2+9x^2=154/9}}}put in general form. changed mixed fraction -17 1/9 to improper fraction 154/9.
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center is (0,1/3), radius is {{{sqrt(154/9)=sqrt(154)/3}}}
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