Question 24900
The first line has the SAME slope as y = 2/3x + 1, which is m = 2/3.  If its y intercept is -3, then the equation must be 
{{{y = (2/3)x - 3}}}


The second line must be perpendicular to 2x - 3y = 6.  You have to solve for y in order to find the slope:
2x-3y = 6
-3y = -2x + 6


Divide both sides by -3:
{{{y =(-2x)/(-3) + 6/(-3)}}}
{{{y = (2/3)x -2}}}, so the slope of this line is {{{2/3}}}.


The slope of a line PERPENDICULAR to this line is the NEGATIVE RECIPROCAL of {{{2/3}}}, which is {{{-3/2}}}.  If the line has a y intercept of 2, then the equation of the line is 
{{{y = (-3/2)x+ 2}}}.


R^2 at SCC