Question 178884
distance = rate * time
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can be frustrating at times, cant it!!!!
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we know that the total distance will be what seperates them which is 6000 ft. At this point we dont know how far each will travel. lets call the rescuers distance d and the climbers 6000-d. We know time will be equal and we will call that t. rate for climber is 2000ft/hr and rescuers 1000ft/hr
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climber:6000-d=2000t....eq 1
rescuers: d=1000t.......eq 2
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take d's value from eq 2 and plug it into eq 1
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6000-1000t=2000t
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3000t=6000
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{{{t=2}}}hours
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how far will the rescuers ascend or how far will the climber descend in 2 hours
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climber will descend:2000(2)=4000 ft
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rescuers will ascend:1000(2)=2000 ft
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so they will meet at 12500-4000=8500ft or 6500=2000=8500ft
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{{{highlight(8500)}}}feet