Question 178750
{{{ a[1]=3*2^0=3*1=3}}}
{{{ a[2]=3*2^1=3*2=6}}}
{{{ a[3]=3*2^2=3*4=12}}}
{{{ a[4]=3*2^3=3*8=24}}}
{{{ a[5]=3*2^4=3*16=48}}}
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{{{ a[n]=3*2^(n-1)}}}
{{{ a[100]=3*2^(99)}}}
or approximately
{{{ a[100]=3*6.338x10^(29))}}}
{{{ a[100]=1.901x10^(30))}}}