Question 178751
let n and p be the number of nickles and pennies
:
n+p=52...........eq 1
.05n+.01p=1.2....eq 2
:
rewrite eq 1 to n=52-p and plug that value into eq 2
:
.05(52-p)+.01p=1.2
:
2.6-.05p+.01p=1.2
:
-.04p=-1.4
:
{{{highlight(p=35)}}}number of pennies
:
{{{highlight(n=52-35=17)}}}number of nickels