Question 178702
Given that z=3y+2/y-1, express y in terms of z
and hence find the value of y when z=1/2
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z=(3y+2)/(y-1)
zy - z = 3y + 2
zy-3y = 2+z
y(z-3) = z + 2
y = (z+2)(z-3)
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Let z = 1/2
y = (5/2)/(-5/2)
y = -1
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Cheers,
Stan H.