Question 178567
I'm assuming that this is your problem.
{{{-(3/2)k+(5/9)=-8-(1/9)k}}}
If it's not, please re-post with parentheses in the appropriate locations denoting fractions,
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First off, let's get rid of denominators. 
Multiply both sides by (2*9),
{{{-(3/2)(2*9)k+(5/9)(2*9)=-8(2*9)-(1/9)(2*9)k}}}
{{{-(3*9)k+(5*2)=-8(2*9)-(1*2)k}}}
{{{-27k+10=-144-2k}}}
{{{-25k=-154}}}
{{{highlight(k=154/25)}}}