Question 178678
How do you find the zeros of the equation 3x to the second power = 6x + 1
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Rearrange:
3x^2 - 6x - 1 = 0
Use the quadratic formula:

x = [6 +-sqrt(36 - 4*3*-1)]/6

x = [6 +- sqrt(48)]/6

x = [6 +- 4sqrt(3)]/6

x = 1 +- (2/3)sqrt(3)
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Cheers,
Stan H.