Question 178625
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*[tex \LARGE \text {          }{{10 sqrt{6}} \over {sqrt{15}}}] 


Multiply by 1 in the form of *[tex \LARGE \text { } \frac {sqrt {15}}{sqrt {15}}], thus:


*[tex \LARGE \text {          } \left( \frac{10 sqrt{6}}{sqrt{15}} \right) \left(\frac {sqrt{15}}{sqrt{15}} \right) = \frac {10 sqrt{90}}{15} = \frac {30 sqrt{10}}{15} = 2 sqrt {10} ]









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