Question 178568
let x and y be the amount of tea that sells fo 3.45 and 2.15 a pound respectively
:
x+y=80....................eq 1
3.45x+2.15y=2.75(80)......eq 2
:
rewrite eq 1 to x=80-y and plug that value into eq 2
:
3.45(80-y)+2.15y=2.75(80)
:
276-3.45y+2.15y=220
:
-1.3y=56
:
{{{highlight(y=43.07)}}}pounds of $2.15 tea
:
{{{highlight(x=80-43.07=36.93)}}}pounds of $3.45 tea