Question 178557
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let {{{x}}}=population in 1969.
34% increase of {{{x}}} = {{{273.10x10^6}}} (population in 1999.
Translating into detailed eqn:
{{{x+0.34(x)=273.10x10^6}}}
{{{x(1+0.34)=273.10x10^6}}}
{{{x*cross(1.34)/cross(1.34)=cross(273.10x10^6)203.80597x10^6/cross(1.34)}}}
{{{highlight(x=203.80597x10^6)}}} ANSWER --->population in 1969.
Check:
34% population in 1969=popl'n in 1999 - popl'n in 1969
{{{0.34(203.80597x10^6)=(273.10-203.80597)x10^6}}}
{{{69.29403x10^6=69.29403x10^6}}}
thank you,
Jojo</pre>