Question 178563
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Via Slope_intercept Form: {{{y=mx+b}}}
Point (5,3) with {{{Slope=m=-4/3}}}
{{{3=(-4/3)(5)+b}}}
{{{3=-20/3+b}}}
{{{b=3+(20/3)=(9+20)/3}}}
{{{b=29/3}}}----> Y-Intercept
Then the Line eqn follows---->{{{y=(-4/3)x+(29/3)}}}
Standard Form: {{{highlight((4/3)x+y=29/3)}}}
Aw we see the graph:
{{{drawing(400,400,-5,12,-5,12,grid(1),graph(400,400,-5,12,-5,12,(-4/3)x+(29/3)),green(circle(5,3,.14)))}}}
Thank you,
Jojo</pre>