Question 178536
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To make your drawing, just plot the two points and then draw a line through both of them.


{{{drawing(
400, 400, -8, 2, -2, 8,
grid(1),
circle(-4,0,.2),
locate(-4,-.5,P1(-4,0)),
circle(0,6,.2),
locate(.2,5.9,P2(0,6)),
graph(
400, 400, -8, 2, -2, 8,
y=(3/2)x + 6
))}}}


Any line parallel to this line has the same slope.  So you need to calculate the slope of this line.


The slope of a line passing through two points *[tex \Large \left( x_1,y_1 \right)] and *[tex \Large \left( x_2,y_2 \right)] is given by:


*[tex \Large m = \frac {y_1 - y_2}{x_1 - x_2}].


Your points are:   *[tex \Large ( -4,0 )] and *[tex \Large ( 0,6 )], so just plug in the values and do the arithmetic:


*[tex \Large m = \frac {0 - 6}{-4 - 0}].  You can do your own arithmetic.  You don't absolutely <i><b>have</b></i> to reduce the fraction to lowest terms, but it makes things much tidier if you do.


To make it easy to create your second line, you need another point on your second line -- you are already given the first one, the origin *[tex \Large ( 0,0 )].


Use the point-slope form of the equation of a line, *[tex \Large (y - y_1)=m(x - x_1)] to create an equation for your second line.  Since the slopes have to be the same so that the lines are parallel, use the value of *[tex \Large m ] you calculated above and insert the coordinates of the origin for *[tex \Large x_1] and *[tex \Large y_1].  Like this:


*[tex \Large (y - 0)=m(x - 0)] which simplified is  *[tex \Large y=mx] (*[tex \Large m ] being replaced by the value you calculated above) .  Now pick any value for *[tex \Large x] that you like other than zero (I would pick 2 myself, but it is entirely up to you), and calculate the value of *[tex \Large y].  These two values will give you the coordinates of a second point for your new line.  Plot the new point, plot the origin, and connect the dots.

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