Question 178513
hope I get this right because it is written so the 2x is under the 1 but I am thinking you meant (1/2)x or x/2
:
{{{((1/2x)+(1/4))/(4/(x^2-1))}}}
:
invert and multiply bottom fraction
:
{{{((1/2x)+(1/4))((x^2-1)/4)))}}}
:
{{{((x+2)/4x)((x^2-1)/4)}}}.........found common denominator on terms on left
:
{{{(x+2+(x)(x^2-1))/4x)}}}.....combined numerator terms over common denominator after multiplying right side by x/x to get common denominator of 4x
:
{{{(x^3+2)/4x}}}combined like terms