Question 178516
{{{((4x+4)/(4x^2-1))+(3/(1-2x))}}}
:
{{{((4x+4)/(2x+1)(2x-1))-3/(2x-1)}}} factored denominator of 1st term and changed 1-2x in the denominator of the 2nd term by changing signs
:
{{{((4x+4)/(2x+1)(2x-1))-3(2x+1)/(2x+1)(2x-1)}}} multiplied 2nd term by 2x+1 top and bottom to form common denominator
:
{{{(4x+4-6x-3)/(2x+1)(2x-1)}}}added numerators together
:
{{{-(2x-1)/(2x+1)(2x-1)}}}..combined like terms in numerator
:
{{{-1cross((2x-1))/(2x+1)cross((2x-1))}}}(2x-1)terms cancelled each other
:
{{{highlight(-1/(2x+1))}}}