Question 178465
Given 1 point and the slope of a line I can
find the equation of that line
(2,-4) is a point on the line
If {{{m}}} is the slope, {{{-(1/m)}}} is 
perpendicular to the line with that slope
{{{-(1/(3/2)) = -(2/3)}}}
The general slope-intersect form of a line is
{{{y = mx + b}}}
So far I have
{{{y = -(2/3)x + b}}}
To determine {{{b}}} I use the given point
{{{-4 = -(2/3)*2 + b}}}
{{{-4 = -(4/3) + b}}}
{{{-12 = -4 + 3b}}}
{{{3b = -8}}}
{{{b = -(8/3)}}}
The equation of the line is
{{{y = -(2/3)x -(8/3)}}}
To find the {{{y}}} in (-4,y),
{{{y = -(2/3)*(-4) - (8/3)}}}
{{{y = 8/3 - (8/3)}}}
{{{y = 0}}} answer