Question 178353
For part a, you need the equation for compounding n times per year:
{{{A=P(1+(r/n))^(nt)}}}
So here, P=760,000, r=0.05, n=1, and t=5.  So,
{{{A=760000(1+(0.05/1))^(1*5)=969973.99}}}
So to know the interest, we just subtract: $969,973.99-$760,000=$209,973.99.

Now, for part b), the formula for continuous compounding is
{{{A=Pe^(rt)}}}
So,
{{{A=760000e^(0.05*5)=975859.32}}}
So the interest is $975859.32-$760000=$215,859.32