Question 178357
{{{(3x+1)/4-x/5=x-2}}}
Alright, if you're anything like the rest of the world, you do not like fractions.  So as a first step, let's get rid of them.  If we multiplied both sides of the equation by 4 would that get rid of all the fractions?  What about 5?  No to both.  We need to find the LCM of 4 and 5 in order to get rid of both.  This is 20.  So if we multiply both sides of the equation by 20, it should eliminate all fractions.  So,
{{{20(3x+1)/4-20x/5=20(x-2)}}}
{{{5(3x+1)-4x=20x-40}}}
{{{15x+5-4x=20x-40}}}
{{{11x+5=20x-40}}}
{{{5=9x-40}}}
{{{45=9x}}}
{{{x=5}}}