Question 178308

Distance(d) equals Rate(r) times Time(t) or d=rt;  r=d/t and t=d/r

When Train B passes the station, Train A is 12 min or 1/5 hr past the station and this equates to 80*(1/5) mi=16 mi ahead of train B
Let t=time required for Train B to catch train A (counting from 7:32 pm)

Now we know that when the two trains have travelled the same distance, then train B will have caught Train A, so:
 90t=16+80t  subtract 80t from each side
90t-80t=16+80t-80t collect like terms
10t=16  divide each side by 10
t=1.6 hr=1 hr 36 min-------------------time that elapses before Train B catches Train A
So, 7:32 pm+1 hr 36 min=9:08 pm time that Train B catches Train A

Does this help???------ptaylor