Question 178268
Simplify. Assume that each radical represents a real number.
(√(n+1) +√n)( √(n+1) -√n)
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{{{(sqrt(n+1) + sqrt(n))*(sqrt(n+1) - sqrt(n))}}}
Treat the radicals as x and y, then it's (x+y)*(x-y) = x^2-y^2
So it's 
(n+1) - n
= 1