Question 178161
215) [(2x – 5) / (x – 2)(x + 6)] + [(x^2 – 2x + 1) / (x – 2)(x + 6)]

[(2x – 5) / (x – 2)(x + 6)] + [(x^2 – 1)^2 / (x – 2)(x + 6)]

The denominators are the same so combine the numerators to get:

= [2x - 5 + x^2 -2x + 1] / [(x-2)(x+6)]

= [x^2-4] / [(x-2)(x+6)]

= (x+2)/(x+6)
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217.) 2/(x-3) + 3/(3-x)
Modify to get:
2(x-3) - 3 (x-3)

= (2-3)/(x-3

= -1/(x-3)

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Cheers,
Stan H.