Question 178031
1.{{{4k+3h=12}}}
2.{{{4k-h=4 }}}
Subtract eq. 2 from eq. 1, this will leave an equation only in h.
{{{(4k+3h)-(4k-h)=12-4}}}
{{{4k-4k+3h-(-h)=8}}}
{{{4h=8}}}
{{{highlight(h=2)}}}
Use either eq. 1 or eq. 2 to solve for k.
{{{4k-h=4}}}
{{{4k-2=4}}}
{{{4k=6}}}
{{{highlight(k=6/4=3/2)}}}