Question 24884
You need to put this equation in slope-intercept form;
y=mx+b
3x+2y=10
2y=-3x+10
y=-{{{3/2}}}x+10
Now plot the first point, which is given by your equation, where b=y-intercept.
y-intercept=10
slope=-{{{3/2}}}
So the first point is (0,10), and with the slope -{{{3/2}}} plot your next point.
So from that point on the y-axis, go down 3 and over 2, that is point 2.
{{{graph (400,400, -12,12,-4,18, (3/2)x+10)}}}
=)