Question 178026
(81) to the 1/3 power divided by (729) to the 1/5 power
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81^(1/3) = 3*(3^(1/3))

729^(1/5) = [3^(6)]^(1/5) = 3*(3^(1/5))

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Dividing you get [3*(3^(1/3))] / [3*(3^(1/5))]

The "3" factors cancel and you need to subtract the exponents to get:

= 3^(1/3 - 1/5)

= 3^(2/15)

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Cheers,
Stan H.