Question 177844
I think you meant – x – y + z  =  2 for the 3rd equation in System # 1
				5x  +  4y  -  z  =  1 ---------(i)
				2x  -  2y  +  z  =  1 ---------(ii)
				- x  -  y   +   z  =  2 --------(iii)

Adding eq (i) and (ii)		7x  + 2y   =  2 -------------(iv)
Subtracting eq (iii) from eq (ii)	3x  -   y   =  -1 -------------(v)
Multiplying eq (iv) by 1		7x  +  2y  =  2 -------------(vi)		
Multiplying eq (v) by 2		6x  - 2y   =  -2 ------------(vii)
Adding eq (vi) and eq (vii)	13x     =    0
					x     =     0
Substituting 0 for x in eq (v) 	3(0)  -   y   =  -1
					y   =     1
Substituting 0 for x, & 1 for y in eq (i)    5x  +  4y  -  z  =  1
				5(0)  +  4(1)  -  z  =  1
				0   +   4   -   z   =   1
					z   =     3

Therefore, x   =   0   ;   y  =  1   ;   z   =    3

You should be able to do the rest, although they seem to be missing information, or written incorrectly.