Question 177932
If you have a quadratic equation in the form {{{y=ax^2+bx+c}}}, the x-coordinate of the vertex is always {{{-b/(2a)}}}.  Then to find the y-coordinate, you just plug in the x you just found back into the equation.  So in this case, a=1, b=4, and c=3.  So the x-coordinate of the vertex is {{{-4/(2*1)=-2}}}.  So to find y, 
{{{y=(-2)^2+4(-2)+3=4-8+3=-1}}}
So the vertex is (-2,-1).