Question 24864
With further clarification, it seems that the original problem was to find the derivative of a function {{{k(x) =sin((1/4)*e^(-8x))}}}.  It turns out that the derivative of k(x) is 
k'(x) ={{{(1/4)*cos((1/4)*e^(-8x))*(-8e^(-8x))}}}.


The question was actually, how do you simplify this answer!  


k'(x) = {{{-2 e^(-8x)*cos((1/4)e^(-8k))}}}


By the way, Calculus is usually not as hard as the algebra it takes to simplify it!!  If you want to be GOOD at Calculus, make sure you have a GOOD algebra background before you get there!!


R^2 at SCC