Question 177834
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a) Given roots are 5 and -2, therefore *[tex \Large x = 5] and *[tex \Large x = -2]


If *[tex \Large x = 5], then *[tex \Large x - 5 = 0]


and


If *[tex \Large x = -2], then *[tex \Large x + 2 = 0]


Now you have the two factors for your quadratic:


*[tex \Large (x - 5)(x + 2) = 0]


Using FOIL:


*[tex \Large x^2 - 3x - 10 = 0]


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Do the other one the same way.  Hint:  *[tex \Large x = \frac {-3}{4}] so *[tex \Large x + \frac {3}{4}=0] so *[tex \Large 4x + 3 = 0]


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