<PRE><B>Question 177797</B>
Well I am not God, but he has used me on occasion
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lets call D the total distance
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1+(1/2)D+(1/3)D+1=D...all these interval lengths together make up the distance
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2+(3/6)D+(2/6)D=D..(made fraction like terms so we could add them
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2+(5/6)D=D....combined fractional terms
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(1/6)D=2......subtracted 5/6D from both sides
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{{{highlight(D=12)}}}km......(multiplied both sides by 6)</PRE>