Question 177677
<FONT FACE="Times New Roman" SIZE="4">Just substitute 30 for V and then solve for T.  The thing is, you really don't have a hang time function.  What you have is vertical leap as a function of time.  What you need is hang time as a function of vertical leap.  Just divide both sides by 48 and then take the square root:


*[tex \huge T = sqrt{\frac {V}{48}}]


Now all you have to do is substitute 30 for V and do the arithmetic.</FONT>