Question 24852
First of all, please see my THREE Lesson Plans in algebra.com about Graphing, especially the one about graphing the line in Slope Intercept Form.  


In this problem, y =-2x+3, it is in the form y=mx+b, so the y intercept is the number term, which is 3, and the slope is the coefficient of x, which is {{{m= (rise)/(run) = (-2)/1}}}.


To graph this, locate the y-intercept, by going UP three units on the y-axis, and put the first point.  Then, with your pencil on this point, move DOWN 2 units (this is the RISE), and go 1 unit to the RIGHT (this is the RUN), and put the second point.  Then connect the points, and it should look like this:

{{{graph (400, 400, -10,10,-10,10, -2x+3 )}}}


R^2 at SCC