<PRE><B>Question 177664</B>
 x + 3 over x^2-5x all this times (3x^2-17x+10)
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[(x+3)/(x^2-5x)][3x^2-17x+10]

Factor where possible:
[(x+3)/(x(x-5))][3x^2-15x-2x+10]

= [(x+3)/(x(x-5))][3x(x-5)-2(x-5)]

= = [(x+3)/(x(x-5))][(3x-2)(x-5)]


Cancel the common factor to get:

= [(x+3)/x][(3x-2)

= (3x^2 +7x +6)/x
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Cheers,
Stan H.



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